Hello,
if the polynomial X2+ax2+5 and x2-2x2+a are divided by (x+2) leave the same remainder, find the value of a
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Answered by
27
Heya!!☻
Here's your answer!!!
____________________________
Let the given polynomial be f(x) = x²+ax²+5
g(x) = x²-2x²+a
Given that when f(x) and y(x) are divided by the (x+2) we get the same remainder.
That is f(2) = g(2)
put x=2 in both f(x) and g(x)
(2)²+a(2)²+5 = (2)²-2(2)²+a
4+ 4a+5 = -4-8+a
9+4a = 13+a
3a = -13
so, a = 13/3
______________________________
GLAD HELPS YOU,
it helps you,
thank you ☻
@vaibhavhoax
Here's your answer!!!
____________________________
Let the given polynomial be f(x) = x²+ax²+5
g(x) = x²-2x²+a
Given that when f(x) and y(x) are divided by the (x+2) we get the same remainder.
That is f(2) = g(2)
put x=2 in both f(x) and g(x)
(2)²+a(2)²+5 = (2)²-2(2)²+a
4+ 4a+5 = -4-8+a
9+4a = 13+a
3a = -13
so, a = 13/3
______________________________
GLAD HELPS YOU,
it helps you,
thank you ☻
@vaibhavhoax
Angelina83:
awsm explained..... Yash ^_^
Answered by
0
Step-by-step explanation:
therefore, P × 24(25)/2 × 10/100 × 1/12 = 5P/2
therefore, Amount deposited + 1 = Maturity amount
24 P + 5P/2 = 132500
therefore,
53P/2 = 132500
therefore,
₹5000
Glad help you,
it helps you,
thanks.
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