Question

hello.... Koi answer kardo please ​

Answer 1

y=sinx logx dy/DX
dy/DX=sinx logx+xcosx logx + xsinx .1/x
=sinx logx+xcosx logx+sinx

Answer 2

y=x sinx logx

dy/dx=d(x sinx logx)/dx

we have to take individual terms and differentiate them.

dy/dx=sinx logx d(x)/dx + x logx d(sinx)/dx + x sinx d(logx)/dx

=sinx logx + x cosx logx + x sinx 1/x

=sinx logx + x cosx logx + sinx

Hope this helps.