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siddhartharao77:
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Answered by
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Let 2^x = 3^y = 12^z= k
So,
2 = k^(1/x)
3= k^(1/y)
12= k^(1/z)
We know that
2*2*3 =12
k^(1/x)*k^(1/x)*k^(1/y) = k^(1/z)
k^(1/x+1/x+1/y) = k^(1/z)
We know if base is same on both sides,then powers must be equal.
2/x + 1/y = 1/z
So this is the correct relation, I think the one asked in the ques is wrong.
So,
2 = k^(1/x)
3= k^(1/y)
12= k^(1/z)
We know that
2*2*3 =12
k^(1/x)*k^(1/x)*k^(1/y) = k^(1/z)
k^(1/x+1/x+1/y) = k^(1/z)
We know if base is same on both sides,then powers must be equal.
2/x + 1/y = 1/z
So this is the correct relation, I think the one asked in the ques is wrong.
Answered by
2
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