Question

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Question-- A hemispherical bowl has a radius of 3.5 cm. What would be the volume of water it would contain.​

Answer 1

Step-by-step explanation:

$\huge\underline\purple{\mathcal Answer :-}$

SOLUTION:--

Given in question:- The volume of water the bowl can contain

= 2/3π³

= 2/3 x 22/7 x 3.5 x 3.5 x 3.5 cm³

= 89.8 cm³.

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Answer 2

HERE IS YOUR ANSWER:--------

GIVEN:- RADIUS OF HEMISPHERE (HEMISPHERICAL BALL)=3.5

TO FIND:- VOLUME OF WATER HEMISPHERICAL BOWL CAN CONTAIN.

WE KNOW, VOLUME OF HEMISPHERE =2/3 πr^3

A/Q,

=>2/3πr^3

=>2/3×22/7×3.5×3.5×3.5

=>89.8 cm^3.

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SINCE WE KNOW THAT VOLUME OF WATER WILL BE EQUAL TO TOTAL VOLUME OF THE HEMISPHERE THAT IS HEMISPHERICAL BALL.