Question

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Answer 1

Step-by-step explanation:

length of cylendriacal pipe = 50m.

diameter.............,................. = 14cm.

convert cm into m = 14/100.

=》 0.14m

so, radius of cylindrical pipe = 0.14/2.

radius = 0.7

$volume \: of \: pipe = \pi {r}^{2} h$

so putting on formula.

$so \: we \: get \: \pi \times (0.7) {}^{2} \times 50$

$we \: get \: 24.5\pi \: m {}^{3}$

Now, length of cuboidal pond =50m

Breadth ........................,............ = 44m

Heigth......................................... = 21cm.

=》 convert into m = 21/100.

0.21m

Volume of cuboidal pond. l × b × h.

=》 50 × 44 × 0.21

=》 462 m^3.

$= \frac{volume \: of \: pipe}{volume \: of \: cuboidal \: pond}$

$\frac{24.5\pi}{462}$

0.16 sec.

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