hello mates✌️✌️
Good morning..☀️☀️
plz answer the below question
if a current of 3.2 ampere per second flows through a conducting wire calculate the number of electrons passing through the wire.
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Answers
Answered by
1
Hi,
Use formula (I=ne/t)
Here, I=current,
n=number of electron
e=electron =1.6 x 10¯¹9 C
Then calculate,
I=ne/t
10= n x 1.6 x10¯¹9 / 1
n= 10/1.6 x 10¯¹9
n = 6.25 x 10¹9.
mahendrasinghsaharan:
what
Answered by
3
hey mate here is your answer✨✨
I=3.2A. , e=1.6×10^-19
I=Q/t
Q=It
Q=3.2×1
Q=3.2
Q=ne
3.2=n×1.6×10^-19
3.2/1.6×10^-19=n
n=2×10^19
n=0.2×10^20
therefore number of electron is 0.2×10^20
hope it's helpful___________
I=3.2A. , e=1.6×10^-19
I=Q/t
Q=It
Q=3.2×1
Q=3.2
Q=ne
3.2=n×1.6×10^-19
3.2/1.6×10^-19=n
n=2×10^19
n=0.2×10^20
therefore number of electron is 0.2×10^20
hope it's helpful___________
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