Question

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Please solve this question

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Answer 1

Explanation:

we know that , heat loss = heat gain .

maximum heat loss by copper

block = mSdT

= 2500g X 0.39jg - 1k - 1 x ( 500 -0) K

= 487,500 j = ML

now

487,500 j = ML

where M is the mass of ice melted and L is the latent heat fusion .

487,500j = M X 335 jg -1

M = 1455.22 , g = 1.45522 kg .

HOPE THIS WILL HELP MY DEAR FRIEND.

option (b) is your answer

Answer 2

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$\mathfrak{The\:Answer\:is}$

Mass of the copper block, m = 2.5 kg = 2500 g

Rise in the temperature of the copper block, Δθ = 500°C

Specific heat of copper, C = 0.39 J g^–1 °C^–1

Heat of fusion of water, L = 335 J g^–1

The maximum heat the copper block can lose,

Q = mCΔθ

= 2500 × 0.39 × 500

= 487500 J

Let m1 g be the amount of ice that melts when the copper block is placed on the ice block.

The heat gained by the melted ice,

Q = m1L

∴ m1 = Q / L

= 487500 / 335

= 1455.22 g

Hence, the maximum amount of ice that can melt is 1.455 kg.

$\boxed{Hope\:This\:Helps}$

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