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ABCD quadrilateral. angle ABC = 90 deg.
hence, AB² + BC² = AC² --- (1) using Pythagoras theorem.
AD² = ( AB² + BC² ) + CD² given,
= AC² + CD² ---- (2)
In the triangle ACD, AD has to be a hypotenuse and angle ACD must be 90 deg. as per Pythagoras theorem.
OR
ABCD quadrilateral. angle ABC = 90 deg.
hence, AB² + BC² = AC² --- (1) using Pythagoras theorem.
AD² = ( AB² + BC² ) + CD² given,
= AC² + CD² ---- (2)
In the triangle ACD, AD has to be a hypotenuse and angle ACD must be 90 deg. as per Pythagoras theorem.
hence, AB² + BC² = AC² --- (1) using Pythagoras theorem.
AD² = ( AB² + BC² ) + CD² given,
= AC² + CD² ---- (2)
In the triangle ACD, AD has to be a hypotenuse and angle ACD must be 90 deg. as per Pythagoras theorem.
OR
ABCD quadrilateral. angle ABC = 90 deg.
hence, AB² + BC² = AC² --- (1) using Pythagoras theorem.
AD² = ( AB² + BC² ) + CD² given,
= AC² + CD² ---- (2)
In the triangle ACD, AD has to be a hypotenuse and angle ACD must be 90 deg. as per Pythagoras theorem.
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