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show that any positive odd integer is of the form of 4q + 1 or 4q + 3 where q is some integer
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positive odd integer is of the form of 4q + 1 or 4q + 3
let a,b be positive integerand B = 4
a=bq+r
put B = 4 in equation 1
a=bq+r q>0 and n= 1,2,3
substitute r =0= a= 4q
substitue r=1= 4q+1
substitute r=2 =4q+2
substitute r =3= 4q+3
since 4 q and 4q + 3 are divisible by 2 so4 q and 4q + 2 or not an odd integer
remaining cases equation 4 and 5 or odd integer
hence any positive odd integer or in the form of 4q + 1 or 4q+ 3
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Answer:
1,3,5,7,9,11 put this value in q
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