hello please do thus both question fast if anyone will gife meat the first i will mark him or her as brainlist
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hi
here's your answer
1. since all the angles of a triangle sum upto 180
so,
(x-40)+(x-20)+(x/2-10)=180
2x+x/2-70=180
5x/2=180+70
5x/2 = 250
5x = 250*2
x = 50*2
x = 100
now put the value of x.
therefore, the angles will be
I angle = 100-40(x-40)
= 60
II angle = 100-20(x-20)
= 80
III angle = 100/2-10(x/2-10)
=50-10
= 40
2. in this question also, we will use the angle sum property, i.e., a+b+c = 180
let us take the angle to be x
now the equation formed will be
x+2x+3x = 180
6x = 180
x = 30
now put the value of x
therefore the angles will be
I angle = x
= 30
II angle = 2*30(2x)
= 60
III angle = 3*30(3x)
= 90
hope it helps.
here's your answer
1. since all the angles of a triangle sum upto 180
so,
(x-40)+(x-20)+(x/2-10)=180
2x+x/2-70=180
5x/2=180+70
5x/2 = 250
5x = 250*2
x = 50*2
x = 100
now put the value of x.
therefore, the angles will be
I angle = 100-40(x-40)
= 60
II angle = 100-20(x-20)
= 80
III angle = 100/2-10(x/2-10)
=50-10
= 40
2. in this question also, we will use the angle sum property, i.e., a+b+c = 180
let us take the angle to be x
now the equation formed will be
x+2x+3x = 180
6x = 180
x = 30
now put the value of x
therefore the angles will be
I angle = x
= 30
II angle = 2*30(2x)
= 60
III angle = 3*30(3x)
= 90
hope it helps.
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