hello please solve please don't give meaningless answers ...
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any comments welcome
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dineshmehta1991:
i have considered A and B at corner of trianglular circuit
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hello friend...!!
A) in the first diagram , upper 3 resistors are in series and bottom 3 resistors are in series therefore ,
let us consider R1 as upper part and R2 as lower part , implies ,
R1 = 1 ohm + 1 ohm + 1 ohm ( in series R = r1 + r2 + r3 )
implies R1 = 3 ohm . similarly R2 = 3 ohm .
R1 AND R2 are parallel therefore the total resistance of diagram ( 1 ) is,
1 / R = 1 / R1 + 1 / R2 .
1 / R = 1 / 3 + 1 / 3 = 2 / 3
implies R = 3 / 2-----------------------( answer )
B) in the second diagram the upper two resistors each of with resistance 4 ohm are in series
therefore , R = R1 + R2
R = ( 4 + 4 ) ohm
R = 8 ohm this 8 ohm is parallel with 4 ohm
1 / R = 1 / 4 + 1 / 8 = 3 / 8
R = 8 / 3 --------------------------( answer )
c) in third question ,
let us consider the first square , where the upper two resistors f each resistace 2 ohm are in series simillarly lower two resistors of each resistace 2 ohm are in series .
therefore , in the first box , the upper total resistance is
r1 = 2 ohm + 2 ohm = 4 ohm similarly bottom total resistance is equal to 4 ohm
the upper and bottom are parallel
implies , 1 / r = 1 /r1 + 1 / r2 = 1 / 4 + 1 / 4 = 2 / 4
implies r = 4 / 2 = 2 ohm . ---------------( 1 )
similarly in the second square box the total resistance is 2 ohm ----( 2 )
the third resistor = 2 ohm -----------( 3 )
equation 1 & 2 & 3 are three reistors that are series therefore
R = ( 2 + 2 + 2 ) ohm
R = 6 ohm------------------------( answer )
D) in 4th question ,
let us solve the upper part first ,
where the each resistor of resistance 2 ohm are parallel .
so 1 / r = 1 / r1 + 1 / r2 = 1 / 2 + 1 / 2 = 2 / 2
implies , r = 2 / 2 = 1 ohm ---------( 1 ) { RIGHT HAND SIDE}
similarly r = 1 ohm ------------------( 2 ) { LEFT HAND SIDE }
here equation ( 1 ) and equation ( 2) are series .
so , R 1 = 1 ohm + 1 ohm = 2 ohm-----------------( 3) { COMPLETE UPPER PART }
similarly the total resistance in the complete lower part is
R 2 = 2 ohm----------------( 4 ) { COMPLETE LOWER PART }
equation (3 ) and ( 4 ) are parallel in nature therefore ,
1 / R = 1/ R1 + 1 / R2
1 / R = 1 / 2 + 1 / 2 = 2 / 2
R = 1 ohm -----------------------------------( answer )
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therefore for
first diagram R = 3 / 2 OHM
second diagram R = 8 /3 OHM
third diagram R = 6 OHM
fourth diagram R = 1 OHM .
----------------------------------------------------------------------------
hope it helps...!!!
A) in the first diagram , upper 3 resistors are in series and bottom 3 resistors are in series therefore ,
let us consider R1 as upper part and R2 as lower part , implies ,
R1 = 1 ohm + 1 ohm + 1 ohm ( in series R = r1 + r2 + r3 )
implies R1 = 3 ohm . similarly R2 = 3 ohm .
R1 AND R2 are parallel therefore the total resistance of diagram ( 1 ) is,
1 / R = 1 / R1 + 1 / R2 .
1 / R = 1 / 3 + 1 / 3 = 2 / 3
implies R = 3 / 2-----------------------( answer )
B) in the second diagram the upper two resistors each of with resistance 4 ohm are in series
therefore , R = R1 + R2
R = ( 4 + 4 ) ohm
R = 8 ohm this 8 ohm is parallel with 4 ohm
1 / R = 1 / 4 + 1 / 8 = 3 / 8
R = 8 / 3 --------------------------( answer )
c) in third question ,
let us consider the first square , where the upper two resistors f each resistace 2 ohm are in series simillarly lower two resistors of each resistace 2 ohm are in series .
therefore , in the first box , the upper total resistance is
r1 = 2 ohm + 2 ohm = 4 ohm similarly bottom total resistance is equal to 4 ohm
the upper and bottom are parallel
implies , 1 / r = 1 /r1 + 1 / r2 = 1 / 4 + 1 / 4 = 2 / 4
implies r = 4 / 2 = 2 ohm . ---------------( 1 )
similarly in the second square box the total resistance is 2 ohm ----( 2 )
the third resistor = 2 ohm -----------( 3 )
equation 1 & 2 & 3 are three reistors that are series therefore
R = ( 2 + 2 + 2 ) ohm
R = 6 ohm------------------------( answer )
D) in 4th question ,
let us solve the upper part first ,
where the each resistor of resistance 2 ohm are parallel .
so 1 / r = 1 / r1 + 1 / r2 = 1 / 2 + 1 / 2 = 2 / 2
implies , r = 2 / 2 = 1 ohm ---------( 1 ) { RIGHT HAND SIDE}
similarly r = 1 ohm ------------------( 2 ) { LEFT HAND SIDE }
here equation ( 1 ) and equation ( 2) are series .
so , R 1 = 1 ohm + 1 ohm = 2 ohm-----------------( 3) { COMPLETE UPPER PART }
similarly the total resistance in the complete lower part is
R 2 = 2 ohm----------------( 4 ) { COMPLETE LOWER PART }
equation (3 ) and ( 4 ) are parallel in nature therefore ,
1 / R = 1/ R1 + 1 / R2
1 / R = 1 / 2 + 1 / 2 = 2 / 2
R = 1 ohm -----------------------------------( answer )
--------------------------------------------------------------------------
therefore for
first diagram R = 3 / 2 OHM
second diagram R = 8 /3 OHM
third diagram R = 6 OHM
fourth diagram R = 1 OHM .
----------------------------------------------------------------------------
hope it helps...!!!
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