hello
Please solve this question attached in this image
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Hi
Please see the attached file !
Please see the attached file !
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Anonymous:
Tremendous answer! =_=
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Hey friend here is ur answer ,
common difference (d)= 200
number of terms (n) = 20
sum of 20 terms (S20) = 66000
so , S20 = n/ 2 [2a + (n-1 ) d ]
66000 = 20/2 [ 2a + 19 × 200]
66000 = 10 [ 2a + 3800]
6600 = 2a + 3800
6600 = 2 ( a+ 1900)
3300 = a + 1900
3300 -1900 = a
1400 = a
a = 1400
so , He saved 1400Rs in first year .
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common difference (d)= 200
number of terms (n) = 20
sum of 20 terms (S20) = 66000
so , S20 = n/ 2 [2a + (n-1 ) d ]
66000 = 20/2 [ 2a + 19 × 200]
66000 = 10 [ 2a + 3800]
6600 = 2a + 3800
6600 = 2 ( a+ 1900)
3300 = a + 1900
3300 -1900 = a
1400 = a
a = 1400
so , He saved 1400Rs in first year .
HOPE U LIKE MY ANSWER☆☆☆
Plzz mark it as a brainliest
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