Hello, pls answer this question with steps, I need explanation, if u know then pls do it, no useless answers pls. Thanks in advance.
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Let us assume : x= root(6+root(6 + root(6 + ………
So,
x= root(6+x)
x^2=6+x
x^2-x-6=0
(x-3)(x+2)=0
So, x=3 or -2.
But taking -2 as the answer would mean we are taking root of (-2) . Considering the fact that x belongs to the set of real numbers , we discard the solution x=-2.
So the answer is x =3.
Make me brainlist plz plz
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now stop by my answers
have a great day
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