Question

Hello ! Pls solve the above sum. Thank you.​

Answer 1

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The first answer I already submitted to you

Now this is second answer

$( {2}^{ - 1} \times {4}^{ - 1}) \div {2}^{ - 2} \\ \\ {2}^{ - 1} \div {2}^{ - 2} \times {4}^{ - 1} \\ \\ {2}^{ - 1} \times {2}^{2} \times {4}^{ - 1} \\ \\ {2}^{ - 1 + 2} \times {4}^{ - 1} \\ \\ {2}^{1} \times {4}^{ - 1} \\ \\ 2 \times {4}^{ - 1} \\ \\ 2 \times \frac{1}{ {4}^{1} } \\ \\ 2 \times \frac{1}{4} \\ \\ \frac{1}{2}$

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Answer 2

$</p><p>\begin{gathered}( {2}^{ - 1} \times {4}^{ - 1}) \div {2}^{ - 2} \\ \\ {2}^{ - 1} \div {2}^{ - 2} \times {4}^{ - 1} \\ \\ {2}^{ - 1} \times {2}^{2} \times {4}^{ - 1} \\ \\ {2}^{ - 1 + 2} \times {4}^{ - 1} \\ \\ {2}^{1} \times {4}^{ - 1} \\ \\ 2 \times {4}^{ - 1} \\ \\ 2 \times \frac{1}{ {4}^{1} } \\ \\ 2 \times \frac{1}{4} \\ \\ \frac{1}{2} \end{gathered}(2−1×4−1)÷2−22−1÷2−2×4−12−1×22×4−12−1+2×4−121×4−12×4−12×4112×4121</p><p></p><p>$

$1 + - 1 \times 4 \\ - 1 \times 4 \\ - 4$