Question

Hello

plz solve on paper


Thankss​

Answer 1

∆T = kb × Wb × 1000 / Mb × Wa

where,

Wb is mass of solute in kg

Mb is molar mass of glucose

Wa is mass of solvent

∆T = 0.52 × 18 × 1000 / 180 × 1000

T - T0 = 0.052

T - 373 = 0.052

T = 373 + 0.052

T = 373.052 K