Hello
plzzzz solve thes 3 question
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6+y-(8+5) =0
6+y-13=0
y-7=0
therefore y = 7
all the above process is done on the basis of divisibility rule of 11
difference between the sum of even and odd digits must be zero or multiple of 11
hope you are satisfied with the answer
6+y-13=0
y-7=0
therefore y = 7
all the above process is done on the basis of divisibility rule of 11
difference between the sum of even and odd digits must be zero or multiple of 11
hope you are satisfied with the answer
SrinadhVura:
please mark as brainliest
Answered by
8
Q.8 ) 9261 = 9 × 1029 = 9 × 3 × 343 = 9 × 3 × 7 × 7 × 7 = 3 × 3 × 3 × 7 × 7 × 7
Similarly,
10648 = 8 × 1331 = 8 × 11 × 11 × 11 = 2 × 2 × 2 × 11 × 11 × 11.
Hence
Cube root of 9261 = 3 × 7 = 21
Cube root of 10648 = 2 × 11 = 22
Hence Answer is 21 /22
Q.9 ) It is given that 31z5 is multiple of 3 hence using the divisibility test of 3 sum of it's digits should be divisible by 3
3 + 1 + z + 5 = 9 + z = multiple of 3
Hence z can be 0 , 3 , 6 , 9
Q.10 ) It is given that 68y5 is divisible by 11 hence using the divisibility test of 11 difference between sum of odd places and sum of even places should be 0 or in multiple of 11.
Sum of odd places = 5 + 8 = 13
Sum of even places = y + 6
Difference between sum of odd place and even place = 13 - (y+6) = 13 - y - 6 = 7 - y
In order to be a multiple of 11 it should be 0 or multiple of 11
hence 7 - y = 0
y = 7
Similarly,
10648 = 8 × 1331 = 8 × 11 × 11 × 11 = 2 × 2 × 2 × 11 × 11 × 11.
Hence
Cube root of 9261 = 3 × 7 = 21
Cube root of 10648 = 2 × 11 = 22
Hence Answer is 21 /22
Q.9 ) It is given that 31z5 is multiple of 3 hence using the divisibility test of 3 sum of it's digits should be divisible by 3
3 + 1 + z + 5 = 9 + z = multiple of 3
Hence z can be 0 , 3 , 6 , 9
Q.10 ) It is given that 68y5 is divisible by 11 hence using the divisibility test of 11 difference between sum of odd places and sum of even places should be 0 or in multiple of 11.
Sum of odd places = 5 + 8 = 13
Sum of even places = y + 6
Difference between sum of odd place and even place = 13 - (y+6) = 13 - y - 6 = 7 - y
In order to be a multiple of 11 it should be 0 or multiple of 11
hence 7 - y = 0
y = 7
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