Question

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Find the probability that a number chosen at random from the integers between 5 and 16 inclusive is a multiple of 3 or a multiple of 2.

Answer 1

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$<b><u>Numbers between 5 and 16 are:-$

6, 7, 8, 9, 10, 11, 12, 13, 14 , 15 and 16.

Therefore, total number of outcomes =11

Numbers inclusive between 5 and 16 which are divisible by 2 or 3 are-

6 , 8, 9 ,10 ,12, 14 and 15.

Number of favourable outcomes = 7

Therefore, probability of getting a number which is either a multiple of 2 or 3 is:

$p(e) = \frac{7}{11}$

HENCE, THE REQUIRED PROBABILITY IS = 7 / 11.

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Answer 2

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➡️Numbers between 5 and 16 are:-

6, 7, 8, 9, 10, 11, 12, 13, 14 , 15 and 16.

Therefore, total number of outcomes =11

Numbers inclusive between 5 and 16 which are divisible by 2 or 3 are-

6 , 8, 9 ,10 ,12, 14 and 15.

Number of favourable outcomes = 7

Therefore, probability of getting a number which is either a multiple of 2 or 3 is:

p(e) = \frac{7}{11}p(e)=

11

7

HENCE, THE REQUIRED PROBABILITY IS = 7 / 11.

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