Physics, asked by ZiaAzhar89, 9 months ago

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QUESTION for JEE ASPIRANT

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Answered by sagarnirapure914
37

Answer :–

(A) — (q)

(B) — (r) & (s)

(C) — (r) & (s)

(D) — (p), (q) & (r)

Explanation :–

(A) When a wire is connected across a charged capacitor, the is heated.

(B) When a wire moved with constant velocity in a uniform magnetic field, a constant emf develops between the ends of the wire and constant charge appears at the ends of the wire.

(C) When a wire placed parallel to an external electric field, there is no electric field inside the conducting wire but induced charges will appear at its end.

(D) When a batter of constant emf is connected to the ends of wire, a constant potential difference is developed across the ends of wire, resulting in the flow of a constant current through the wire which heats the wire.

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