Question

❤️❤️❤️Hello public ❤️❤️❤️
⏩Two vertices of a triangle are (3,2) ,(-2,1) and its centroid is
$(\frac{5}{3} - \frac{1 }{3} )$
find the third vertex of the triangle ❇️❇️​

Answer 1

Let third vertex be C(x,y).

Two vertices are (3,2) and (-2,1)

Coordinates of centroid of triangle are:

=> (x + 3 - 2/3, y + 2 + 1/3)

=> (x + 1/3, y + 3/3)

Given:

Centroid is (5/3, -1/3).

=> (x + 1/3) = (5/3)  and  (y + 3/3) = (-1/3)

=> (x + 1) = 5  and (y + 3) = -1

=> x = 4 and y = -4.

Hence, the third vertex of the triangle is C(4,-4)

Answer 2

Answer:

(4,-2)

Step-by-step explanation:

centroid=[( x1+x2+x3)/3,(y1+y2+y3)/3]

thus (3-2+x)/3=5/3

x=(+4)

similarly for y coordinate

y=(-2)

therefore coordinate of third vertex ={4,-2}

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hope it helps...