Hello !!!
QUESTION :-
A Railway Half Ticket costs half the full fare but the reservation charges are same on a Half Ticket as a full ticket . One reserved first class ticket from stations A to B cost rupees 2530 . Also, 1 reserved class ticket and 1 reserved first class half ticket from station A to B cost rupees 3810 .Find the full first class fare from station A to B and also the reservation charges for a ticket .
ALL THE BEST !!!
Answers
SOLUTION☺️❤️✌️
Let x be the cost of full class A to B.
Let y be the cost of reservation.
Since a reserved 1st class ticket cost Rs.2530
=)x+y= 2530............(1)
Since one full and one half 1st class reserved tickets cost Rs.3810
=)3/2x+2y= 3810..........(2)
Thus, equation (1) and (2) from the system of Equations.
Multiply Equation (2) by 2 and rewrite the Equation (2) as .....(3
Let us solve the system of equations(3) and (1)
=)3x+4y= 7620
=)x+y= 2530
Multiply equation (1) by 3, we get:
=)3x+ 3y= 7590........(4)
Subtract equation (4) from equation (3) we get:
=) 3x+4y-3x-3y= 7620-7590
=) 4y-3y= 30
=) y= 30
Substitute the value of y in equation (1) to get the value of x
=) x+y= 2530
=) x+30= 2530
=) x= 2530-30
=) x= 2500
Thus, the 1st class ticket from A to B is 2500 and the reservation cost Rs.30.
hope it helps ✔️❣️
Answer:
2500,30
Step-by-step explanation:
Cost of full first class fare be 'x' and the reservation charges be 'y'.
(i)
One reserved first class ticket from A to B cost 2530.
x + y = 2530.
(ii)
1 reserved class ticket and reserved 1st class half ticket costs 3810.
⇒ (x + y) + (x/2 + y) = 3810
⇒ x + y + x/2 + y = 3810
⇒ 2x + 2y + x + 2y = 7620
⇒ 3x + 4y = 7620
On solving (i) * 3 & (ii), we get
3x + 3y = 7590
3x + 4y = 7620
-----------------------
-y = -30
y = 30
Substitute y = 30 in (ii), we get
⇒ 3x + 4y = 7620
⇒ 3x + 4(30) = 7620
⇒ 3x + 120 = 7620
⇒ 3x = 7500
⇒ x = 2500
First class fare = 2500
Reservation charges = 30
Hope it helps!