Question

HELLO☺☺
show that the diagonals of a square are equal and bisect each other at 90 degree​

Answer 1

Step-by-step explanation:

lets divide a square into two by taking the diagonals as common

abcd is a square and ac and db are the diagonals

in triangle abc and triangle dbc

angle abc = angle dcb = 90 degree ( all angles are 90 degree in a square )

ab = dc ( all sides are equal in a square )

bc = bc ( common side )

therefore triangle abc congurent to dbc through sas congruence rule

now ac = db by cpct

so diagonals ac and bc are equal