hello!!
Soln plz ♥️
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VishalRajvir:
nice dp
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Answered by
5
We know that
F=G(M1)(M2)/r^2
Given that mass of two bodies is doubled
So M1=2M1.....M2=2M2
Distance between The centeres is halved
R=R/2
F=G(2M1)(2M2)/(R/2)^2
F=4G(M1)(M2)/(R^2/4)
F=16F.
Answered by
12
Hey!!
Let the masses be m1 and m2, distance between centre be r.
Original gravitational force
F (g) = G × m1 × m2 / r²
According to question,
New mass = m1' = 2m1 & m2' = 2m2 .
r` = r/2
So gravitational force
F' (g) = G × m1' × m2' / r`²
= G × 2m1 × 2m2 / (r/2)²
= 4×4 × G × m1 × m2 / r²
= 16 F
Hence gravitational force will become 16times.
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