World Languages, asked by Anonymous, 11 months ago

hello!!


Soln plz ♥️ ​

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Answers

Answered by Bharadwaj981
5

We know that

F=G(M1)(M2)/r^2

Given that mass of two bodies is doubled

So M1=2M1.....M2=2M2

Distance between The centeres is halved

R=R/2

F=G(2M1)(2M2)/(R/2)^2

F=4G(M1)(M2)/(R^2/4)

F=16F.


Crystall91: Yes! that's what i thought
Crystall91: I got so confused because of that answer before
apurw23: yaa dear it's correct
apurw23: i make silly mistake in calculation
Answered by Anonymous
12

Hey!!

Let the masses be m1 and m2, distance between centre be r.

Original gravitational force

F (g) = G × m1 × m2 /

According to question,

New mass = m1' = 2m1 & m2' = 2m2 .

r` = r/2

So gravitational force

F' (g) = G × m1' × m2' / r`²

= G × 2m1 × 2m2 / (r/2)²

= 4×4 × G × m1 × m2 /

= 16 F

Hence gravitational force will become 16times.

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