Question

Hello
Solve it
[4/5+{6/7+(2/5+1/7)}]​

Answer 1

Answer:

SOLUTION

Step-by-step explanation:

[4/5+{6/7+(2/5+1/7)}]

THEN,

the solution is

[4/5+{6/7+(19/35)}]

[4/5+{6/7+19/35}]

[4/5+{7/5}]

[4/5+7/5]

11/5

HENCE,VERIFIED

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Answer 2

➤ Answer :-

${\tt \longrightarrow \bigg[\dfrac{4}{5} + \bigg\{\dfrac{6}{7} + \bigg(\dfrac{2}{5} + \dfrac{1}{7} \bigg) \bigg\} \bigg]}$

First, we should solve the smaller bracket............

${\tt \longrightarrow \dfrac{2}{5} + \dfrac{1}{7}}$

Convert them into like fractions by taking the LCM of the denominators i.e, 5 and 7.

LCM of 5 and 7 is 35.

${\tt \longrightarrow \dfrac{2 \times 7}{5 \times 7} + \dfrac{1 \times 5}{7 \times 5}}$

${\tt \longrightarrow \dfrac{14}{35} + \dfrac{5}{35} = \dfrac{14 + 5}{35}}$

${\tt \longrightarrow \dfrac{19}{35}}$

Now, we should solve the second bracket.......

${\tt \longrightarrow \dfrac{6}{7} + \dfrac{19}{35}}$

Convert them into like fractions by taking the LCM of the denominators i.e, 7 and 35.

LCM of 7 and 35 is 35.

${\tt \longrightarrow \dfrac{6 \times 5}{7 \times 5} + \dfrac{19}{35} = \dfrac{30 + 19}{35}}$

${\tt \longrightarrow \dfrac{49}{35} = 1 \dfrac{14}{35}}$

Now, we should solve the big bracket.........

${\tt \longrightarrow \dfrac{4}{5} + \dfrac{49}{35}}$

Convert them into like fractions by taking the LCM of the denominators i.e, 5 and 35.

LCM of 5 and 35 is 35.

${\tt \longrightarrow \dfrac{4 \times 7}{5 \times 7} + \dfrac{49}{35} = \dfrac{28 + 49}{35}}$

${\tt \longrightarrow \dfrac{78}{35} = \boxed{\tt 2 \dfrac{8}{35}}}$

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More to know....................

• BODMAS is a rule which is applied in mathematics. It has some regulations also. We should always solve the small bracket first and the big next. The division should be done first and subtraction at last.

In BODMAS :-

• B denotes Brackets

• O denotes OF (multiplication)

• D denotes Division

• M denotes Multiplication

• A denotes Addition

• S denotes Subtraction