Question

hello!! solve it pls
x=2y+6 then show that x^3-8y^3-36xy-216​

Answer 1

$\huge\mathfrak{\underline{Answer:-}}$

$\mathfrak{\underline{given\: x=2y+6}}$

$\sf x-2y=6$

$\sf (x-2y){}^{3}=6{}^{3}$

$\sf x{}^{3}-8y{}^{3}-6xy(x-2y)=216$

$\sf x{}^{3}-8y{}^{3}-6xy(6)=216$

$\sf x{}^{3}-8y{}^{3}-36xy=216$

$\sf x{}^{3}-8y{}^{3}-36xy-216=0$

$\sf So\:the\:value\:of\: x{}^{3}-8y{}^{3}-36xy-216=0$

Answer 2

Step-by-step explanation:

hola mate.

see the attachment

hope it helps you