hello solve the question plz... this photo.
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ΔABC is an isosceles triangle.
⟹ AB=AC.
(2) BC=CE.
Since AB=AC,
∴∠ABC=∠ACB [Since angles opposite to equal sides of a triangle are equal]
∴180o−∠ABC=180o−∠ACB
∠DBC=∠ECB ………..(1)
[ since ABD and ACE are straight lines].
In triangles DBC and ECB,
∠DBC=∠ECB (from (1))
BD=CE (given)
BC=BC (common side)
∴ΔDBC∼ΔECB [by SAS criteria].
So ,since triangles are congruent,
∴DC=EB.
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