Question

Hello


Solve this equation and find the value of " x " and " y " respectively .


Thanks ×D

Answer 1

x^4 +x^2y^2 +y +y^4 = (x^2 +y^2)^2 x^2y^2 =(x^2 +y^2 -xy)(x^2 +y^2 +xy)

x^2 -xy+y^2 =19
x^2+xy+ y^2 = 49

2x^2 +2y^2 =68
x^2 +y^2 =34

34 -xy =19
(x+y)^2 -2xy =34

xy= 15
(x+y)^2 -30=34
(x+y)^2 =64

xy = 15
x+y =8
x^2 -8x +15=0
x=3 x=5
y= 5 y=3


xy = 15
x+y = -8
x^2+8x+15=0
x= -5 x= -3
y = -3 y = -5