Question

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Answer 1

Explanation:

$\huge\bf{\mid{\overline{\underline{Question:-}\mid}}}$

A gas cylinder can withstand a pressure of 15atm. The pressure of cylinder is measured 12 atm at 27°C . Up to which temperature limit cylinder will not burst.

$\huge\bf{\mid{\overline{\underline{ANSWER:-}\mid}}}$

$\huge\bold{Given:-} \\ \\ P_{1} = 12 atm \\ P_{2} = 15 atm \\ T_{1} = 27 + 273 = 300 K \\ T_{2} = ? \\ \\ \huge\bold{Formula:-} \\ \\ PV= nRT \\ \\ P \propto T \\ \\ \frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} \\ \\ \implies \frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} \\ \\ \implies \frac{12}{300} = \frac{15}{T_{2}} \\ \\ \boxed{ \implies T_{2} = 375 K} \\ \\ For \: \: Celsius.. \\ \\ (375 - 273) \: C = 102 \: C \\ \\ \huge\boxed{ T_{2} = 102 \: C}$

So, (b) is correct ✅

Answer 2

Which is correct option