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Solve:(X-A)(X-B)(X-C)......(X-Z)
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4
Q:Solve:(X-A)(X-B)(X-C)......(X-Z)
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Given that,
Solve:(X-A)(X-B)(X-C)......(X-Z)
Now, though the question seems to be tricky but its quiet easy!!
In the series, one term would also come(X-X) and the result of that term will be 0.
Thus, the rest of the terms multiplied with zero, the final answer turns out to be Zero(0).
Therefore,
(X-A)(X-B)(X-C)......(X-Z)=0
Answered by
5
Q: (X-A) (X-B) (X-C) ............ (X-Z)
= (X-A) × (X-B) (X-C)....... (X-X) (X-Y) (X-Z
= (X - A) × (X - B) × (X-C) × ....... × 0 ×(X-Y) ×(X-Z)
= 0
Hence,
Answer = 0
We know that if we multiply by 0 then we get 0. In this question, At a time we get (X-X) which is equal to 0. therefore, when we multiply whole with 0 then we get 0.
Anonymous:
thanks :)
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