Math, asked by Anonymous, 1 year ago

HELLO!!!

Solve:(X-A)(X-B)(X-C)......(X-Z)

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Answers

Answered by Anonymous
4
\boxed{\boxed{\boxed{\huge{\texttt{Hello!!}}}}}

Q:Solve:(X-A)(X-B)(X-C)......(X-Z)

{\boxed{\huge{\mathsf{Solution:-}}}}
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Given that,

Solve:(X-A)(X-B)(X-C)......(X-Z)

Now, though the question seems to be tricky but its quiet easy!!

In the series, one term would also come(X-X) and the result of that term will be 0.

Thus, the rest of the terms multiplied with zero, the final answer turns out to be Zero(0).

Therefore,

(X-A)(X-B)(X-C)......(X-Z)=0

\huge{\underline{\underline{\mathfrak{Hope It Helps!!}}}}
Answered by Anonymous
5
 \huge{\mathfrak {Solutions :-}}


Q: (X-A) (X-B) (X-C) ............ (X-Z)

= (X-A) × (X-B) (X-C)....... (X-X) (X-Y) (X-Z
= (X - A) × (X - B) × (X-C) × ....... × 0 ×(X-Y) ×(X-Z)
= 0


Hence,
Answer = 0


We know that if we multiply by 0 then we get 0. In this question, At a time we get (X-X) which is equal to 0. therefore, when we multiply whole with 0 then we get 0.

Anonymous: thanks :)
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