Question

hello.....
tell correctly.....

Answer 1

Heya !!!

✓2 , ✓8 , ✓18 , ✓32

✓2 , ✓2 × 2 × 2 , ✓3 × 3 × 2 , ✓2 × 2 × 2 × 2 × 2

✓2 , 2✓2 , 3✓2 , 4✓2

Here,

First term (T1) = ✓2

Second term (T2) = 2✓2

And,

Third term (T3) = 3✓2

Common Difference (D) = T2-T1 = 2✓2-✓2 = ✓2

Also,

Common Difference (D) = T3-T2 = 3✓2-2✓2 = ✓2

As we can see that common Difference is equal.

So,

✓2 , ✓8 , ✓18 , ✓32 is forming an AP.





17th term = A + 16D = ✓2 + 16 × ✓2 = ✓2 + 16✓2


=> 17✓2

★ HOPE IT WILL HELP YOU ★

Answer 2

Bonjour!

Given A.P. = √2, √8, √18, √32

The given A.P. can also be written as;

=> √2, 2√2, 3√2, 4√2

d = 2√2 - √2 = √2

= 3√2 - 2√2 = √2

= 4√2 - 3√2 = √2

As, the d(common difference) in the given A.P. is same so the series is in A.P.

n = 17th

d = √2

a = √2

an = a + (n - 1)d

= √2 + (17 - 1)√2

= √2 + 16√2

= 17√2

So, the 17th term of A.P. is 17√2

Hope this helps...:)