Question

Hello ☺️
$\huge\mathrm\red{Question}$

Solve ;
A part of monthly hostel charges is fixed and the remaining depends on the number of days one has taken food in the mess.When a student A takes food for 20 days, she has to pay Rs.1000 as hostel charges whereas a student B, who takes food for 12 days, pays Rs.1180 as hostel charges.Find the fixed charges and the cost of food per day.

No spam ✖️
No copy and paste answer ✖️
( don't give irrelevant answer for points )

spam = 20 Answer report .( Be aware )
​​

Answer 1

Answer:

Let the fixed charge be Rs. x and the variable charge be Rs. y per day.

It is given that when a student A takes food for 20 days she has to pay Rs. 1000 as hostel charges, therefore,

x+20y=1000⇒x=1000−20y.....(1)

It is also given that when a student B takes food for 12 days she has to pay Rs. 1180 as hostel charges, therefore, we have:

x+26y=1180

 

Let us now substitute the value of x from equation 1 as follows:

x+26y=1180⇒1000−20y+26y=1180⇒−20y+26y=1180−1000⇒6y=180⇒y=6180⇒y=30

Now, substitute the value of y in equation 1:

x=1000−(20×30)=1000−600=400

Therefore, x=400 and y=30.

Hence, the fixed charges is Rs. 400 and the variable charges is Rs. 30 per day.

Answer 2

$\huge\pink{\mid{\fbox{\tt{Answer}}}{\mid}}$

Let the fixed charged be "x" and the cost of food per day is 'y'

(I) A takes food for 20 days she has to pay 1000 .

$\pink\longrightarrow$ x+20y=1000

(II)B takes food for 26 days pays 1180

$\pink\longrightarrow$x+26y=1180

On solving (I) ,(II) we get:-

$\pink\longrightarrow$x+20y=1000

$\pink\longrightarrow$x+26y=1180

____________________________________,

$- 6y = - 180$

$y = 30$

Substitute y = 30 in (No II)

$\pink\longrightarrow$x+26y=1180

$\pink\longrightarrow$x+26(30)=1180

$\pink\longrightarrow$x+780=1180

$\pink\longrightarrow$ x = 1180 - 780

$\pink\longrightarrow$x=400

Hence ,the fixed charged is 400

The cost of food per day is 30