Hello!!
![{p}^{4} - 81 {p}^{4} - 81](https://tex.z-dn.net/?f=+%7Bp%7D%5E%7B4%7D++-+81)
Factorize the following
Answers
Answered by
6
hey mate
here is your answer
![= {p}^{4} - 81 \\ = ( {p}^{2} + 9)( {p}^{2} - 9) \\ = ( {p}^{2} + 9)(p + 3)(p - 3) = {p}^{4} - 81 \\ = ( {p}^{2} + 9)( {p}^{2} - 9) \\ = ( {p}^{2} + 9)(p + 3)(p - 3)](https://tex.z-dn.net/?f=+%3D+++%7Bp%7D%5E%7B4%7D++-+81+%5C%5C++%3D+%28+%7Bp%7D%5E%7B2%7D++%2B+9%29%28+%7Bp%7D%5E%7B2%7D++-+9%29+%5C%5C++%3D+%28+%7Bp%7D%5E%7B2%7D++%2B+9%29%28p+%2B+3%29%28p+-+3%29)
hope it helps
here is your answer
hope it helps
Anonymous:
thank you
Answered by
1
=========================================
♠ p⁴ - 81
★ p⁴ - 81
We can write it as
= (p²)² - (9)²
♦ Using identity : (a² - b²) = (a + b)(a - b),
= (p² + 9) (p² - 9)
We can still write it as
= [(p² + 9) (p)² - (3)²]
♦ Using identity : (a² - b²) = (a + b)(a - b),
= (p² + 9) (p + 3) (p - 3)
♥ •°• p⁴ - 81 = (p² + 9) (p + 3) (p - 3)
=========================================
Thank you.. @^_^
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