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The length of the parallel sides of a trapezium are in the ratio 4:7 if the height of trapezium is 14 m and it's area is 385 sq.m, find the length of it's parallel sides.
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Answered by
50
area of trapenzium= 1/2×h×(a+b)
385=1/2×14×(a+b)
385=7×(a+b)
(a+b)=55
ratio is 4:7
a=(4/11)×55=4×5=20 m
b=(7/11)×55=7×5=35 m
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385=1/2×14×(a+b)
385=7×(a+b)
(a+b)=55
ratio is 4:7
a=(4/11)×55=4×5=20 m
b=(7/11)×55=7×5=35 m
HOPE HELPS
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PLS MARK IT AS BRAINLIEST
smartyprince:
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Answered by
49
Given that they are in the ratio of 4:7.
Let the length of the parallel sides be 4x and 7x.
Given that height of trapezium = 14m.
Given Area of trapezium = 385m^2.
We know that Area of trapezium = (1/2) * (sum of parallel sides) * (Distance between them)
= > 385 = (1/2) * (4x + 7x) * (14)
= > 385 = (1/2)(11x) * (14)
= > 385 * 2 = 154x
= > 770/154 = x
= > x = 5.
Now,
One parallel side = 4(5)
= 20.
Another parallel side = 7(5)
= 35
Therefore, the length of its parallel sides are 20 and 35 m.
Hope this helps!
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