Question

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the question is that
If x = acosθ+ bsinθ and y = bcosθ - asinθ , then prove that x^2 + y^2 = a^2 + b^2

Answer 1

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Given, x=acosθ+bsinθ......(1) and y=asinθ−bcosθ......(2). 

Now squaring (1) and (2) and then adding we get,

x2+y2=a2(cos2θ+sin2θ)+2absinθ.cosθ−2absinθ.cosθ+b2(sin2θ+cos2θ)

or, x2+y2=a2+b2.

Answer 2

Answer:

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