Science, asked by DaSecretSoul, 10 months ago

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Conclusion pf Rutherfords experiment​

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Answered by Anonymous
0

Ernest Rutherford was interested in knowing how the electrons are arranged within an atom. Rutherford designed an experiment for this. In this experiment, fast moving alpha (α)-particles were made to fall on a thin gold foil.

  • He selected a gold foil because he wanted as thin a layer as possible. This gold foil was about 1000 atoms thick.
  • α-particles are doubly-charged helium ions. Since they have a mass of 4µ, the fast-moving α-particles have a considerable amount of energy.  

It was expected that α-particles would be deflected by the sub-atomic particles in the gold atoms. Since the α-particles were much heavier than the protons, he did not expect to see large deflections. But, the α-particle scattering experiment gave totally unexpected results .

Observations of Rutherford's scattering experiment

  1. Most of the fast moving α-particles passed straight through the gold foil.
  2. Some of the α-particles were deflected by the foil by small angles.
  3. Surprisingly one out of every 12,000 alpha particles appeared to rebound.
Answered by Anonymous
3

Explanation:

Conclusion of Rutherford's scattering experiment:

Most of the space inside the atom is empty because most of the α-particles passed through the gold foil without getting deflected. Very few particles were deflected from their path, indicating that the positive charge of the atom occupies very little space.

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