Math, asked by Anonymous, 1 year ago

Hello there!

Solve this question :

x² + 3x - 130

By splitting middle term.

Answers

Answered by Brâiñlynêha

$<body bgcolor="pink"> <font color="purple">$

$\bf\huge\red{SOLUTION:-}$

$\sf x{}^{2}+3x-130$

$\sf x{}^{2}+(13-10)x-130$

$\sf x{}^{2}+13x-10x-130$

$\sf x(x+13)-10(x+13)$

$\sf (x+13)(x-10)$

Hope it's help !! ☺️

Answered by Anonymous

$\huge\underline\mathfrak\red{Answer}$

( x - 10 ) ( x + 13 )

$\huge\underline\mathfrak\red{Explanation}$

x² + 3x - 130

x² + 13x - 10x - 130

x( x + 13 ) - 10 ( x + 13 )

( x - 10 ) ( x + 13 )

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