Question

Hello!
tommorow is my maths paper pls quickly send me the solution for this
P.S wish me luck​

Answer 1

Answer:

hey buddy!!

Let numbers be x at onces place & y at tens place so,

10y+x is the digit.

Reversed digit =10x+y

According to the question ,

∴7(10y+x)=4(10x+y)

⇒x=2y⟶(i)

Now,

Given , x−y=3

from equation (i)2y=x substitute in above equation.

2y−y=3

y=3

So ,

x=2y=2⋅3=6

∴ Required original no: is =10y+x=10⋅3+6=36.