Question

HELLO USERS !

^Answer the Question from the attachment with proper explanation^

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Answer 1

HELLO DEAR,

given that:-

mass of each ball = 50g = 50/1000kg = 0.05kg
initial velocity = 16m/s

After collision, the direction of velocity of each ball is reversed on rebounding.

where,

impulse = mass * velocity

now,

impulse imparted = final impulse - initial impulse

=> 0.05 * (-16) - [ 0.05 * (16) ]

=> -0.8 - 0.8

=> - 0.16kgm/s

∴Impulse imparted due to one ball after collision on another would be +0.16kgm/s

$\textbf { I HOPE ITS HELP YOU DEAR , THANKS}$

Answer 2

Hey sista!

Here's your answer!!
------ ----- ------

Mass of each ball = 0.05 kg

Initial velocity of first ball = 16 m/s
Initial velocity of second ball = -16 m/s

Initial momentum of the first ball, p(i)
= 0.05 × 16 = 0.8 kg m/s
Initial momentum of the second ball, p(i)
= 0.05 ×(-16) = 0.8 kg m/s

After collision, the balls rebound without changing the magnitude of their speeds.

So, final momentum of first ball, p(f)
= 0.8 kg m/s
So, final momentum of second ball, p(f)
= 0.8 kg m/s

Impulse imparted to first ball
= Change in it's momentum
= pf - pi = -0.8 - 0.8 = -1.6 kg m/s

Impulse imparted to second ball
= Change in it's momentum
= pf - pi = 0.8 - (-0.8) = 1.6 kg m/s

$hope \: it \: helps \: you....$

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