Question

hello users differentiateit


$\bf Find$
$\frac{dy}{dx } \\ \\ \sqrt{x } + \sqrt{y} = \sqrt{a}$
​

Answer 1

$\bf \fbox{Given} \downarrow$

$\sqrt{x} + \sqrt{y} = \sqrt{a}$

$\bf Differentiate\: both \: sides \: w.r.t\: we \:get,$

$\frac{1}{2 \sqrt{x} } + \frac{1}{2 \sqrt{y} } \frac{dy}{dx} = 0 \\ \\ \frac{1}{2 \sqrt{y} } \frac{dy}{dx} = - \frac{1}{2 \sqrt{x} } \\ \\ \frac{dy}{dx} = - \frac{2 \sqrt{y} }{2 \sqrt{x} } \\ \\ \frac{dy}{dx} = - \sqrt{ \frac{y}{x} }$

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