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check the solution and learn the identities dear...
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I knew that identity but was trying in another way
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u can do same question in different ways
ohk
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Answered by
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Formula of a^3+b^3
(a+b)(a^2-ab+b^2)
According to the question
3x+2y=20
xy=11/9
Find
27x^3+8y^3
(3x)^3+(2y)^ 3= (3x+2y)(3x^2- 3x×2y+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2- 6×xy+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2- 6×11/9+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2- 66/9+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2- 22/3+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2+2x^2- 22/3)
(3x)^3+(2y)^ 3= (100x^2-440/3)
(3x)^3+(2y)^ 3= (10x^2-440/3
(a+b)(a^2-ab+b^2)
According to the question
3x+2y=20
xy=11/9
Find
27x^3+8y^3
(3x)^3+(2y)^ 3= (3x+2y)(3x^2- 3x×2y+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2- 6×xy+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2- 6×11/9+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2- 66/9+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2- 22/3+2y^2)
(3x)^3+(2y)^ 3= (20)(3x^2+2x^2- 22/3)
(3x)^3+(2y)^ 3= (100x^2-440/3)
(3x)^3+(2y)^ 3= (10x^2-440/3
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