Question

hellpp me with this too.......​

Answer 1

Answer:

Hey, Harsh Sharma here.

Step-by-step explanation:

Check the attachment for your answer

Answer 2

1. f(x) = 2x^2 + 2

Solution:

f(-2) = 2(-2)^2 + 2 = 10
Ordered pairs (-2, 10)

f(-1) = 2(-1)^2 + 2 = 4
Ordered pairs (-1, 4)

f(0) = 2(0)^2 + 2 = 2
Ordered pairs (0, 2)

f(1) = 2(1)^2 + 2 = 4
Ordered pairs (1, 4)

f(2) = 2(2)^2 + 2 = 10
Ordered pairs (2, 10)

See the graph picture below (red)

2. f(x) = 5x^2 + 20x - 1

Solution:

f(-4) = 5(-4)^2 + 20(-4) - 1 = -1
Ordered pairs (-4, -1)

f(-3) = 5(-3)^2 + 20(-3) - 1 = -16
Ordered pairs (-3, -16)

f(-2) = 5(-2)^2 + 20(-2) - 1 = -21
Ordered pairs (-2, -21)

f(-1) = 5(-1)^2 + 20(-1) - 1 = -16
Ordered pairs (-1, -16)

f(0) = 5(0)^2 + 20(0) - 1 = -1
Ordered pairs (0, -1)

See the graph picture below (blue)


Hope this will be helpful to you