Question

Hellw Friends♥️♥️♥️
Plsss ans this

An Alpha particle is accelerated through a potential difference of 2000v what will be the increase in energy in electron volt??
​

Answer 1

Answer:

Charge on α particle is q=2e.

Kinetic energy = work done =qV=2eV=2×10

6

eV=2MeV

Answer 2

$\huge\mathtt\red{Question}$

Aɴ ᴀʟᴘʜᴀ ᴘᴀʀᴛɪᴄʟᴇ ɪs ᴀᴄᴄᴇʟᴇʀᴀᴛᴇᴅ ᴛʜʀᴏᴜɢʜ ᴀ ᴘᴏᴛᴇɴᴛɪᴀʟ ᴅɪғɢᴇʀᴇɴᴄᴇ ᴏғ 2000ᴠ.

ᴡʜᴀᴛ ᴡɪʟʟ ʙᴇ ᴛʜᴇ ɪɴᴄʀᴇᴀsᴇ ɪɴ ᴇɴᴇʀɢʏ ɪɴ ᴇʟᴇᴄᴛʀᴏɴ ᴠᴏʟᴛ?

$\huge\mathtt\red{Solution}$

$\mathtt\orange{we\:know\:that,}$

$\boxed{K.E=charge×P.D}$

$\mathtt\orange{The\:charge\:of\:alpha\:particle\:is\:twice\:an\:electron}$

$\mathtt\orange{Therefore\:charge\:will\:be\:2e.}$

$\mathtt\orange{According\:to\:the\:question}$

$\mathtt\pink{→K.E = 2e\:×\:2000v}$

$\mathtt\pink{→K.E = 4000ev}$

$\huge\mathtt\red{Answer}$

$\boxed{K.E= 4000ev}$