Helo gelp me to solve question number both
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Hello your answer is in photo .
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hiii!!!
here's ur answer...
5. given the hypotenuse of the right angle triangle is 20cm and the ratio of the other two sides is 4 : 3
let the other two sides be 4x and 3x
by Pythagoras theorem :-
==> (4x)² + (3x)² = 20²
==> 16x² + 9x² = 400
==> 25x² = 400
==> x² = 400/25
==> x² = 16
==> x = √16
==> x = 4
hence, the two other sides of the right angle triangle are :-
4x = 4 × 4 = 16cm and 3x = 3 × 4 = 12
6. given the ratio of the sides of the triangle is 3 : 4 : 5
the longest side must be the hypotenuse so let the hypotenuse of the triangle be 5
therefore 3² + 4² = 5²
LHS :-
= 3² + 4²
= 9 + 16
= 25
RHS :-
= 5²
= 25
therefore LHS = RHS
hence, it's proved that it's a right angle triangle.
hope this helps..!!
here's ur answer...
5. given the hypotenuse of the right angle triangle is 20cm and the ratio of the other two sides is 4 : 3
let the other two sides be 4x and 3x
by Pythagoras theorem :-
==> (4x)² + (3x)² = 20²
==> 16x² + 9x² = 400
==> 25x² = 400
==> x² = 400/25
==> x² = 16
==> x = √16
==> x = 4
hence, the two other sides of the right angle triangle are :-
4x = 4 × 4 = 16cm and 3x = 3 × 4 = 12
6. given the ratio of the sides of the triangle is 3 : 4 : 5
the longest side must be the hypotenuse so let the hypotenuse of the triangle be 5
therefore 3² + 4² = 5²
LHS :-
= 3² + 4²
= 9 + 16
= 25
RHS :-
= 5²
= 25
therefore LHS = RHS
hence, it's proved that it's a right angle triangle.
hope this helps..!!
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