Question

Helo guys plz slove this ​

Answer 1

Answer:

p(z)=4z²-2(k+1)z+(k+4)

a=4

b= -2(k+1)

c=(k+4)

Since, equation has equal roots

Therefore, D=0

D=b²-4ac

b²-4ac=0

(-2(k+1))²-4(4)(k+4)=0

4(k+1)²-4(4)(k+4)=0

4[(k+1)²-4(k+4)]=0

(k+1)²-4(k+4)=0

Using (a+b)²=a²+b²+2ab

k²+1+2k-4k-16=0

k²-2k-15=0

k²-5k+3k-15=0

k(k-5)+3(k-5)=0

(k+3)(k-5)=0

Therefore, k = (-3) or (5)

Answer 2

Answer:

hope that it helps you....

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