Question

Help!!!

16. The dimensions of a room are 8.6 m 6.4 mx 4 m. It has two doors each measuring 2 m by 1 m
four equal windows in the shape of squares. If the cost of painting the four walls is Rs 4,480 at
Rs 40 per m2. find the size of the windows.
​

Answer 1

Step-by-step explanation:

Total Surface Area of cuboid = 2(lb +bh + hl).

Length =8.6m

Breadth = 5.4m

Height = 4m

now, the length of two doors. = 2m

the breadth " " " " "" "" = 1m

So, area of 2 doors are = 2 × l × b.

= 2 × 2 × 1.

= 4m^2.

length of four windows = 1m

breadth " " " " = 1m

Area of square = 4 × 4 × side.

= 4 × 4 × 1.

= 16m^2.

Now, CSA kf cuboid + area of base rectangle - total area of doors and windows.

=》 2(l + b) + l × b - 20

=》 2(8.6 + 5.4) + 8.6 × 5.4 - 20

=》 2 × 14 + 46.44 - 20.

=》 54.44m^2.

Total cost of plastering= 65.

=》 54.44 × 65

=》 3538.6 rupees.

Please select it as brainlists.

Answer 2

Answer:

please mark me as brainliest