Question

help ....
3rd Questions....

Answer 1

HEY DARLO ❤❤❤.....
here is ur answer....

Answer 2

(x+2)(x+3)+(x-3)(x-2)-2x(x+1)=0
${x}^{2}+2x+3x+6+{x}^{2}- 3x - 2x + 6 - 2 {x}^{2} - 2x = 0 \\ - 2x + 12 = 0 \\ - 2x = - 12 \\ x = \frac{12}{2} = 6$