Physics, asked by vaishu1213, 1 year ago

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Answered by DarkFrost
0

Acc. to me,

answer is 3

First mark Outgoing and incoming current at npn transister

ib and ic is incoming

ie is outgoing

If you know just apply Kirchoff junction rule to find current --

First

From B to E---because Vbe is given in question

Vb+200000ib-10=Ve------Vb-Ve=Vbe

Vbe+200000ib-10=0

Vbe=0.4

Put and find ib

ib=4.8*10∧-5

Second

From C to E -----because Vce is given in question

Vc+1000ic-10=Ve

Vce=10-1000ic

Vce=4

Put and find ic

ic=6*10∧-3

Current gain =Output current/input current

Output current=ic

Input current=ib

CG=ic/ib

CG=6*10∧-3/4.8*10∧-5

After Solving

CG=125

I hope it Help

Please tell me for any mistake

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