Chemistry, asked by yanikesh, 1 year ago

help and support..pls answer this..

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Answered by annu12p

10 ki power21 i hope it is write co2 process

yanikesh: yes..but the process what

annu12p: ok

apramanik69: 200 mg CO2 = 200/44000 moles of CO2 = 4.54×10^-3 moles of CO2.

apramanik69: Hence the no.of moles removed = (4.54 - 2.89 )×10^-3. Hence the no. Of molecules removed = 1.65×10^-3×6.023×10^23. = 9.93×10^20 = 10^21 (approx.).

annu12p: ye apne answer me likh le na bhai

Answered by Rajalah

The answer is in the image ..
Hope you are satisfied...

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apramanik69: The method is too lengthy.

yanikesh: yea...lengthy..

annu12p: bas ab

Rajalah: It is the most systematic method get marks in exam

annu12p: ok stop it know please

Rajalah: ok

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