Question

Help asap trying to find factor x^2+5x=-4

Answer 1

Step-by-step explanation:

${x}^{2} + 5x + 4 = 0 \\ x = 4 \: \: \: \: or \: \: \: \: \: x = 1 \\ \\ so \: thats \: the \: solution \: of \: following \: quadratic \: equatio$

Answer 2

Step-by-step explanation:

$\Huge\underline{\underline{\sf ANSWER}}\\ {x}^{2} + 5x = - 4 \\ {x}^{2} + 5x + 4 = 0 \\ x = \frac{ - b \: + \: or \: - \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 5 + \: or \: - \sqrt{25 -16 } }{2} \\ x = \frac{ - 5 + 3}{2} \: \: \: \: or \: \: \: \: x = \frac{ - 5 - 3}{2 } \\ x = - 1 \: \: \: \: \: \: \: \: \: \: \: \: or \: \: \: \: x = - 4$