Question

HELP!!!
Circle K has a radius of 8 inches. Diameter AKC is drawn and point F is located on the circle such
that FC = 6. Find the length of FA. (Round to the nearest tenth)

Answer 1

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Answer 2

CONCEPT:

All points in a plane that are at a specific distance from a specific point, the centre, form a circle. In other words, it is the curve that a moving point in a plane draws to keep its distance from a specific point constant.

Area of circle πr²

Circumference=2πr

Angle subtended by the diameter on the semicircle is always a right angle

GIVEN:

Circle K has a radius of 8 inches. Diameter AKC is drawn and point F is located on the circle such that FC = 6

FIND:

Find AF

SOLUTION:

Angle subtended by the diameter on the semicircle is always a right angle

So we can write,∠AFC=90

Using pythagoras theorem,

AF²+FC²=AC²

where

FC=6in

AC=16in

⇒AF=√(16²+6²

        = √292

          = 17.08

          ≈20in

Therefore, length of AF =20 in

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