Question

help class 10 maths, ignore if you dont know ​

Answer 1

We know that,

$\dagger \quad \tan 45^{\circ} = 1$

$\dagger \quad \cos 30^{\circ} = \dfrac{\sqrt{3}}{2}= \sin 60^{\circ}$

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$2\tan^2 45^{\circ} + \cos^2 30^{\circ} - \sin^2 60\degree$

Substituting the values, we get

$\rm\dashrightarrow 2\times (1)^2+\Bigg ( \dfrac{\sqrt{3}}{2} \Bigg )^2 - \Bigg (\dfrac{\sqrt{3}}{2}\Bigg )^2$

$\rm\dashrightarrow 2\times 1+0$

$\bf \dashrightarrow 2$

Hence, 2 is the answer.

Answer 2

Answer:

2 is your answer........